S1xtyJoin Date: 2009-10-25
Post Count: 4491 |
The mathematical community should accept the imaginary number of 1/inf as a constant of which will be called q.
For example, instead of saying that because of limits as x approaches infinite y is 0 you could instead say that if y = 7 that the result would be 7q. I assume this would have some applications in theoretical mathematics and physics. |
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XML1Join Date: 2013-06-26
Post Count: 95 |
This is intriguing. It seems as though you misclicked, though. This is not a mathematical community. If you want people to accept your arbitrary ideas then go somewhere where people care. |
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Weewooo go away, don't come back another day. Kthx |
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S1xtyJoin Date: 2009-10-25
Post Count: 4491 |
I would love if Roblox had a forum for mathematicians, although I remain for that wish to be fulfilled, and instead must consult the closet thing to a math community. |
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Hmm, I don't know your reasoning behind using q as the constant so I don't quite agree on that part. However, a constant with the value of one divided by infinity would be quite useful. |
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S1xtyJoin Date: 2009-10-25
Post Count: 4491 |
I don't have any ideas for fancy symbols right now. So I just used a strange letter. |
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jewelycatJoin Date: 2008-09-10
Post Count: 17345 |
Infinitesimal? |
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S1xtyJoin Date: 2009-10-25
Post Count: 4491 |
Yes, it represents an infinitely small number with the value of 1/inf. But logic also states that 7/inf is larger than 6/inf |
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@weewoo5
You might want to read this
http://mathforum.org/library/drmath/view/62486.html |
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A sum of an infinite series can converge on an integer. |
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ummmmmmmmmmmmmmmmmmmmmmmmmmm i dont get it |
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MettaurSpJoin Date: 2010-03-20
Post Count: 3179 |
I wanna see weewoo selling propane and propane accessories now while Kahn yells "redneck hillbilly neighbor" at him for no apparent reason. |
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AgentFirefoxTop 100 PosterJoin Date: 2008-06-20
Post Count: 22404 |
OP, you make no sense.
n/x for all n in R as x --> inf = 0. Always.
This also means any constant c * n/x for all n, c in R as x --> inf also = 0.
Always.
Plus, even if we do use some arbitrary variable q to hold 1/x as x --> inf, q = 0 anyway, and your proposed notation of 7q = 7*0 = 0 anyway (as x --> inf).
Plus, inf isn't even a number, and thus cannot be represented in equations, so the term 1/inf is complete nonsense from the get-go. |
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The correct mathematical term is that 1/infinite tends towards 0. If you think about it, it actually IS 0.
'But logic also states that 7/inf is larger than 6/inf'
wat.
Infinity is NaN. Not a Number.
infinity == infinity
n < infinity where n is not infinity.
All values that can possibly be written down are smaller than infinity. If you divide a number by infinity, you are not simply dividing a small number by a big number, you are dividing a small number by a concept that is bigger than anything else. Since it isn't really a number, you shouldn't really be able to divide by it, but if you did manage to, you would get 0 for absolutely ANY real number you put as the numerator. |
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So, infinity is not in the set of all real numbers? |
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AgentFirefoxTop 100 PosterJoin Date: 2008-06-20
Post Count: 22404 |
Infinity isn't a number at all. It's a concept. |
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So, it's not in the set of real numbers. |
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toshir0zJoin Date: 2009-11-03
Post Count: 425 |
I propose that weewoo5 leaves this forum and never returns. |
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