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e^x+12e^-x=7
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e^x+12e^-x=7
Celestus
Join Date: 2011-08-15
Post Count: 14873
#147798147
Sunday, October 12, 2014 9:00 AM GMT
No, the 1 is being multiplied by the 12, not added. 12 * e^-x Now when you multiply the whole equation through by e^x, this section in particular will go; 12 * e^0 12 * 1 12
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ChaoticDoom99
Join Date: 2010-11-25
Post Count: 6208
#147798168
Sunday, October 12, 2014 9:01 AM GMT
i'm telling you it's 21
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nonHelperBot
Join Date: 2011-09-30
Post Count: 3070
#147798315
Sunday, October 12, 2014 9:10 AM GMT
Year 8 so haven't learnt said concepts.
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RareMetals
Join Date: 2012-08-01
Post Count: 1226
#147798330
Sunday, October 12, 2014 9:11 AM GMT
Cel, I meant I added an extra e^-x into the equation that wasn't supposed to be there. Idk why I did but I did. :L
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Gentaurg
Join Date: 2011-03-19
Post Count: 8648
#147819523
Sunday, October 12, 2014 5:51 PM GMT
Noobs
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Insangelous
Join Date: 2013-01-29
Post Count: 12854
#147819646
Sunday, October 12, 2014 5:53 PM GMT
1
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Devoi
Join Date: 2013-06-09
Post Count: 5387
#147819941
Sunday, October 12, 2014 5:57 PM GMT
2log(2),log(3)
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Gentaurg
Join Date: 2011-03-19
Post Count: 8648
#147821743
Sunday, October 12, 2014 6:18 PM GMT
Wrong,wrong
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