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SigmuhJoin Date: 2016-03-24
Post Count: 2183 |
If you have calculus you need to quit roblox |
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rev_rbJoin Date: 2016-08-26
Post Count: 58 |
don't you need to simplify it more lol |
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quit roblox god damn, focus on studying, you can ask us though |
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WoolHatJoin Date: 2013-05-19
Post Count: 1873 |
All of these chumps telling you to quit roblox, lmao |
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5ancuJoin Date: 2015-12-31
Post Count: 6771 |
"V(r) = 4/3·πr3"
first off, wtf? that's now how a sphere's volume is determined, it's V(r) = 4/3 · pi · r^3
but the question seems very simple, you just add a parenthesis and instead of r you write r+2
so the solution would be V(r) = 4/3 · pi · (r+2)^3
the parenthesis is necessary in this scenario, so if you haven't put it in there that may very well be your problem
but the question seems to easy for that to be a viable solution, and it's not uncommon that i see you stupid americans doing mathematics in a way more complicated manner than what is necessary |
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5ancuJoin Date: 2015-12-31
Post Count: 6771 |
well the answer that i've given you is essentially what you wrote yourself, but that's the correct answer. so yeah. it may be that you just need to reduce the equation, so
V(r) = 4/3 · pi · r^3 + 8
but idfk you americans are sick sons of b's |
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5ancuJoin Date: 2015-12-31
Post Count: 6771 |
nvm, you need to figure out how much air has to be added, so you just have to reduce the following expression
4/3 · pi · (r+2)^3 - 4/3 · pi · r^3
g'luck |
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SigmuhJoin Date: 2016-03-24
Post Count: 2183 |
"all of these chumps telling you to quit roblox lmao"
salty?
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KIeosJoin Date: 2012-07-18
Post Count: 4917 |
fun fact if you're not an idiot you can manage your time to have fun and pass calculus at the same time |
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I'm not in calculus, but I've taken it.
Do you understand what this question is asking you? |
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Okay folks, listen up! You're working with two volumes.
You have the initial volume, V(r)=(4/3)πr^3
and a final volume, G(r)=(4/3)π(r+2)^3
Your objective is *not* to calculate the final volume, but rather the distance between the two. The amount of air added to inflate the balloon must logically be the difference between the inflated and regular volumes, giving the following expression.
G(r)-V(r)=A(r)
Where G(r)=(4/3)π(r+2)^3 ----the volume of the inflated balloon
and V(r)=(4/3)πr^3 ----the volume of the normal balloon
and A(r)=G(r)-V(r) ----the volume of the air added to inflate the balloon
Since A(r)=G(r)-V(r), we find and simplify:
1. A(r)=(4/3)π(r+2)^3 - (4/3)πr^3
2. A(r)=(4/3)π((r+2)^3-r^3)
Thus, the volume of air required to inflate the balloon to a radius of r+2 inches in terms of π and r is equal to A(r)=(4/3)π((r+2)^3-r^3). That's your answer. |
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TheWhackJoin Date: 2011-09-29
Post Count: 468 |
Cruising down the street with my Ti-84 |
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Uh, let's see, make it like (4/3*π(r+2)^3 - 4/3*π(r)^3)
so, uh, get a freaking calculator. |
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beloxyJoin Date: 2010-08-14
Post Count: 2800 |
Uh I have too much work right now to look at it fully (yeah yeah I know I'm procrsinating) but I'd like to comment that when these guys are saying 4/3, you should probably have it in parenthesis to be safe unless it's actually written vertically in your answer (like if you're using a program like Aleks). |
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5ancuJoin Date: 2015-12-31
Post Count: 6771 |
false just repeated what i said he's not even smart smfh |
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