m27frogyJoin Date: 2009-03-26
Post Count: 4427 |
@ColorfulBody,
We arguing about whether or not 0.9 followed by infinite "9"s is 1. Infinite is the adjective form of infinity. Infinity has a lot to do with this argument. |
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AerideynJoin Date: 2010-01-16
Post Count: 1882 |
1 - 1 = 0
1 - 0.9999.... = 0.0000.. (infinite 0's)
1 = 0.999... |
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booingJoin Date: 2009-05-04
Post Count: 6594 |
lololol
most stupid flame war ever |
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wow this argument/flame war is still alive
and most of you guys don't even know what you're talking about |
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UnBuildJoin Date: 2013-03-22
Post Count: 3233 |
@Aerideyn
No, 1 = 0.999... but not for that reason
x = 0.333...
1/3 = x * 1
1/3 = 0.333...
2/3 = x * 2
2/3 = 0.666...
3/3 = x * 3
3/3 = 0.999...
3/3 = 1 |
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Not really an argument anymore.
Just sort of a discussion.
Also, interesting properties of numbers:
Take the inverse of a prime number. If the decimals repeat, take the repeating decimals, and append a 1 or a prime number to it other than 2. Example:
1/7 = 0.(142857)
"142857".."1"
1428571 is a prime number.
Weird.
1/3 = 0.(3)
"3".."1"
"3".."7"
31 and 37 are prime numbers.
1/11 = 0.(09)
"9".."11"
"9".."37"
911 and 937 are prime numbers.
Perhaps it's just a coincidence.
The Prime Jester of Scripters has spoken. |
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This is getting ridiculous. Seriously? 19 pages? |
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Waffle3zJoin Date: 2011-04-15
Post Count: 266 |
1/9 = 0.(1)2
2/9 = 0.(2)3
3/9 = 0.(3)4
4/9 = 0.(4)5
5/9 = 0.(5)6
6/9 = 0.(6)7
7/9 = 0.(7)8
8/9 = 0.(8)9
9/9 = 1.(0)0 |
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You haven't been reading the past bit, have you?
The Prime Jester of Scripters has spoken. |
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AerideynJoin Date: 2010-01-16
Post Count: 1882 |
There was no error with my proof, there is more than 1 way to show that 0.99.. is 1 you know.. |
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@awsumpwner27
Found a counter-example.
1/41 = 0.(02439)
"02439" + "37" -> "0243937"
0243937 is not a prime number: 83×2939=0243937
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Twitter: https://twitter.com/MarkOtaris |
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Oh, I forgot to mention that they won't always be prime. However, it seems to be that you can append a lot of numbers with prime numbers, and they will be prime. I'm not sure if it's even more likely if it's a prime's inverse if it's a repeating decimal.
Also:
1/41 = 0.(02439)
"02439" + "1" -> "024391"
24391 just happens to be a prime number. Coincidence? I have no idea.
The Prime Jester of Scripters has spoken. |
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1^2 - 0^2 = 1
2^2 - 1^2 = 3
3^2 - 2^2 = 5
4^2 - 3^2 = 7
5^2 - 4^2 = 9
6^2 - 5^2 = 11
7^2 - 6^2 = 13
8^2 - 7^2 = 15
When I was younger, I thought that I could use the above to find prime numbers, or something.
It just turns out that a lot of odd numbers between 1 and 15 happen to be prime. Although, I still find it cool that:
(n+1)^2 - n^2 = 2n+1
The Prime Jester of Scripters has spoken. |
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noliCAIKSJoin Date: 2010-03-08
Post Count: 917 |
@awsumpwner27
(n+1)^2 - n^2
= (n+1)(n+1) - n^2
= n(n+1)+1(n+1) - n^2
= n^2+n+n+1 - n^2
= 2n+1 |
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What is the maximum size if the internet without the protocols running it break apart? |
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databrainJoin Date: 2013-01-01
Post Count: 3342 |
3/3 = x * 3
3/3 = 0.999...
No That's not true.
What makes that statement true?
Everyone posting algebraic proof are getting it wrong.
Like the first algebraic proof statement:
10x - x = 9x = 9.999... - 0.999... = 9 true
9x = 9 where did he get that x? that was never there. Because this was never an equasion to start with
Infinity does not equal 1000000
and 0.9999... is not 1. It is 0.9999
and 0.9999... CANNOT be represented as a fraction, let alone 3/3. Because 0.9999... is
infinity - 1
over
infinity
Emerson wrote an essay on that |
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databrainJoin Date: 2013-01-01
Post Count: 3342 |
I'm with booing. This is a very stupid thread. We all know that they are not equal, and I shall disprove and algebraic proof that you bring up if you'ld like, but I am not oo active on this thread.
Emerson wrote an essay on that |
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databrainJoin Date: 2013-01-01
Post Count: 3342 |
the trick for getting the fraction out of a decimal would be exactly
infinity - 1
over
infinity
Because infinite nines is infinity, and 0.999... = 1 - 0.000...
Emerson wrote an essay on that |
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@databrain
"
In mathematics, the repeating decimal 0.999... (sometimes written with more or fewer 9s before the final ellipsis, or as 0.9, , 0.(9)) denotes a real number that can be shown to be the number one. In other words, the symbols "0.999..." and "1" represent the same number.
" - Wikipedia
The absolute truth disagrees with you, your argument is void. |
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Wikipedia: Indeterminate form
Read the first bit and the rest if you wish. |
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cntkillmeJoin Date: 2008-04-07
Post Count: 49450 |
ZOMG
Why is there an argument over something so stupid?
I mean, who honestly plans on using 0.999... instead of 1 or 0.90? |
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> I'm with booing. This is a very stupid thread. We all know that they are not equal, and I shall disprove and algebraic proof that you bring up if you'ld like, but I am not oo active on this thread.
Wait, booing actually stated somewhere that he believes they are not equal? That's disappointing and not something I'd expect from booing. Then, again, there are many people who have disappointed me by posting what they did in this thread.
Anyway, the only reason I was still arguing some posts ago is that I wanted you all to actually understand you were wrong; it's not like I need any sort of proof to prove I'm right: there is overwhelmingly overwhelming evidence accepted by an overwhelmingly overwhelming number of mathematicians. That 0.(9) is equal to 1 is a logical consequence of the standard number system as it was derived from the axioms from which it was formed.
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Twitter: https://twitter.com/MarkOtaris |
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@databrain: Let's take that first algebraic example one step at a time
(Throughout this I'm using ... to represent a recurring decimal, so 1/3 = 0.333..., for example)
Let x = 0.999...
Hence 10x = 9.999...
(Multiplying both sides by 10)
So 10x - x = 9.999... - x
(Taking x from both sides)
So 10x - x = 9.999... - 0.999...
(As we defined x as 0.999...)
Hence 9x = 9
(As 10x - x = 9x, and 9.999... - 0.999... = 9)
So x = 1
(Divide both sides by 9)
But x is 0.999...
So x = 0.999... = 1 |
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cntkillmeJoin Date: 2008-04-07
Post Count: 49450 |
8 ~= D
Idiots who think that. |
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It is never technically exact because infinity is a concept, not a concrete number. Truly, 1 doesn't equal .9999..., 1 equals .9 repeated and 3/3 (since 1/3 technically equals .3 repeated and 1/3 if we look at decimals without using infinity). However, the whole point of decimals is that they don't use fractions. Thus, we use a 9 repeated forever, and since infinity is not a concrete number, but a concept (as I stated before), .9 repeated infinity times would equal 1 because the limit as n approaches infinity is 1 (it does not pass one but gets extremely close).
Here is more to support what was stated previously. Consider the exponential graph y = 2 to the x power. If x = 0 then y = 1. As x increases, y increases without bound. However, as x decreases, y decreases, but does not fall below zero. For example, if x = -1 then y = 1/2, and if x = -2, y = 1/4. By using real numbers as x values, the y value will never become zero, but if we use the concept of infinity as the x value, the limit becomes the y value, which is zero.
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