|
if there is a door that requires a 4 digit number passcode
how many different possible passcodes are there |
|
|
only 1 passcode is possible - the correct one |
|
KaidouJoin Date: 2011-07-16 Post Count: 5304 |
^ |
|
|
nuh uh
nothing is certain until observed
there are |
|
|
oops i got cut off
there are equally valid possibilities |
|
neongoo51Join Date: 2009-05-12 Post Count: 33061 |
Indefinite.
Because you didn't say if there were 2, 8, 10, or 16 different numbers to choose from.
--[[ Shoot, I accidentally made another post. |
|
miles94Join Date: 2011-10-15 Post Count: 4500 |
we have a winner |
|
|
no, there is only ONE passcode, you said so yourself
"a 4 digit number passcode"
"a" is singular in this case, since "passcode" is singular, you didn't say anything like "set of passcodes"
therefore, only one passcode is needed |
|
|
none
smash the passcode
social life is for stupid face |
|
|
i said number passcode
if not specified, then that covers the scope of all numbers |
|
|
"Because you didn't say if there were 2, 8, 10, or 16 different numbers to choose from"
4 digits = 4 single numbers only, from 0 to 9
"13" is TWO digits, not 1 digit
there are only 10 (1,2,3,4,5,6,7,8,9,0) different kinds of single-digit numbers |
|
neongoo51Join Date: 2009-05-12 Post Count: 33061 |
I was referring to binary, octal, decimal and hexadecimal counting systems.
In hexadecimals, 13 = D.
--[[ Shoot, I accidentally made another post. |
|
|
everyone got it wrong hehehe |
|
|
damnit guys just smash the fking door
social life is for stupid face |
|
neongoo51Join Date: 2009-05-12 Post Count: 33061 |
But either way, 2^4, 8^4, 10^4, and 16^4 for respective counting systems.
I'm incorrect, right?
--[[ Shoot, I accidentally made another post. |
|
|
|
equation
satchel charge + door + detonator = entry |
|
|
|
10,000
What's this madness ye spew? I rate it 14/14 on the pH scale. |
|
|
|
0000 - 9999
total of 10999
hatflip |
|
|
Technically 10^4 different possible combinations.
In simpler terms; ten to the power of 4.
|
|
neongoo51Join Date: 2009-05-12 Post Count: 33061 |
No, this is some sort of trick question.
Hmm.
--[[ Shoot, I accidentally made another post. |
|
neongoo51Join Date: 2009-05-12 Post Count: 33061 |
Fine, I'm just going to throw a wild guess and say ∞ possible combinations...
--[[ Shoot, I accidentally made another post. |
|
|
satchel charge + door + detonator = entry [2]
floodcheck don't you dare glitch up again |
|