i want to get it sounds like fun times
also translate this binary:
01101001 00100000 01110011 01110101 01110000 01110000 01101111 01110010 01110100 00100000 01101000 01110101 01101110 01100111 01100001 01110010 01111001
"omg math no"
q = (b[p] * b^p)
Assume that 'b' refers to the numerical base.
Assume that 'p' refers to the position within the binary number supplied.
I have simplified the process for you. You are welcome.