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darkspear15
#185348836Tuesday, March 15, 2016 1:10 AM GMT

Whats 1+1? Whats 9 - 5 + 84 x 34 + r =?
SpliTech
#185348977Tuesday, March 15, 2016 1:12 AM GMT

9 - 5 + (84 x 34) + r 9 - 5 + 2856 + r 4 + 2856 + r 2860 + r r is a variable, the answer depends gg op entirely original signature
JuiceTheZombie
#185349031Tuesday, March 15, 2016 1:13 AM GMT

"9 - 5 + 84 x 34 + r =?" algebra pleb
darkspear15
#185349163Tuesday, March 15, 2016 1:15 AM GMT

r = 18
JuiceTheZombie
#185349257Tuesday, March 15, 2016 1:17 AM GMT

"r - 18" so 9 - 5 + 84 x 34 + r =2878
darkspear15
#185349391Tuesday, March 15, 2016 1:19 AM GMT

maybe you add? sub? you never know...
Unintelligent_Anon
#185349753Tuesday, March 15, 2016 1:24 AM GMT

Ah, you would like a simple "Algebra" problem, yes? Alright here we go: Suppose that I have a set I containing all of the positive "odd" integers I = {n | n > 0 ^ n % 2 = 1} The first rule of addition is this: n + (n + 1) --> (n (n + 1) - n ) V (n > (n + 1) --> n - (n + 1)) The above states to subtract the lesser integer from the greater integer depending on the position of the quantities. This essentially eliminates the commutative property of addition, and by extension, multiplication. Due to this, "I" is a mathematical group. It has the addition binary operation available.
Unintelligent_Anon
#185355832Tuesday, March 15, 2016 2:54 AM GMT

"Due to this, "I" is a mathematical group. It has the addition binary operation available" A significant flaw in my logic was previously disregarded. Set "I" does not have an "identity element." Consequently, it is impossible for the given set to properly fulfill the definition of a mathematical group. Thus, I will modify the original set criteria in the form (n >= 0), which is "n is greater than or equivalent to zero." That will introduce a valid identity element.

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