of     1   

DoAnAileronRoll
#187696046Tuesday, April 19, 2016 1:56 PM GMT

Prove that: 1 = .999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999...
flybomb
#187696057Tuesday, April 19, 2016 1:57 PM GMT

because if u round up it = 1
Cuilan
#187696120Tuesday, April 19, 2016 1:59 PM GMT

using engineering standard for rounding (upwards to 4 decimal places) we can say that 1 = .9999 (1) because the .9999 will be rounded up though this only really works in the context of engineering since we're lazy and like to keep numbers easy to work with
flybomb
#187696141Tuesday, April 19, 2016 2:00 PM GMT

So basically .999 doesn't equal 1 and it's impossible to ever make an absolute vaue equal another one without a variable
DoAnAileronRoll
#187724798Wednesday, April 20, 2016 12:06 AM GMT

hmmm
legosonic411
#187724882Wednesday, April 20, 2016 12:07 AM GMT

https://www.youtube.com/watch?v=TINfzxSnnIE
Enemy_Down
#187725009Wednesday, April 20, 2016 12:09 AM GMT

The most sequential order to do this is fu**ing up your life. -Everybody down, with Enemy Down!
Proternal
#187725123Wednesday, April 20, 2016 12:11 AM GMT

Another way to think about this is this: Would you agree that 1/3 = .33333...? .3333....is the way to write 1/3 using decimals. If you multiply both sides of the above equation by three you get 1 = .99999...., right? I think the problem you are having, though, is BELIEVING it is true, right? I admit, depending on how you look at it, it can seem false. After all, how can 2 different numbers be equal? The thing is, these 2 numbers AREN'T different. I think saying 1 = .9999... may seem contradictory to us because we aren't realizing that .999.... is a repeating decimal that really does go on forever. Obviously saying 1 = .9 is false, as is saying 1 = .99, 1 = .999, 1 = .9999, etc. But we aren't dealing with finite decimals here. So, you might think of .9999.... as another name for 1, just as .333... is another name for 1/3.
TheShadowMessage
#187725383Wednesday, April 20, 2016 12:15 AM GMT

Sum(1,Infinity) of (9/(10^n)) = 1 - 1/Infinity 1/Infinity = 0 So Sum(1,Infinity) of (9/(10^n)) = 1
VermeiI
#187725573Wednesday, April 20, 2016 12:18 AM GMT

^^ Has it right, though he/she/it probably copy/pasted the answer from some other webpage..
Z007
#187725663Wednesday, April 20, 2016 12:20 AM GMT

quantum mathematics high values of .999... = 1 - your friendly neighborhood medical nerd
DoAnAileronRoll
#187741015Wednesday, April 20, 2016 4:22 AM GMT

o

    of     1